3.22.11 \(\int \frac {1}{(2+3 x) \sqrt [3]{28+54 x+27 x^2}} \, dx\)

Optimal. Leaf size=103 \[ \frac {\log \left (27 \sqrt [3]{2} \sqrt [3]{27 x^2+54 x+28}-81 x-108\right )}{6\ 2^{2/3}}-\frac {\tan ^{-1}\left (\frac {2^{2/3} (3 x+4)}{\sqrt {3} \sqrt [3]{27 x^2+54 x+28}}+\frac {1}{\sqrt {3}}\right )}{3\ 2^{2/3} \sqrt {3}}-\frac {\log (3 x+2)}{6\ 2^{2/3}} \]

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Rubi [A]  time = 0.02, antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {752} \begin {gather*} \frac {\log \left (27 \sqrt [3]{2} \sqrt [3]{27 x^2+54 x+28}-81 x-108\right )}{6\ 2^{2/3}}-\frac {\tan ^{-1}\left (\frac {2^{2/3} (3 x+4)}{\sqrt {3} \sqrt [3]{27 x^2+54 x+28}}+\frac {1}{\sqrt {3}}\right )}{3\ 2^{2/3} \sqrt {3}}-\frac {\log (3 x+2)}{6\ 2^{2/3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((2 + 3*x)*(28 + 54*x + 27*x^2)^(1/3)),x]

[Out]

-ArcTan[1/Sqrt[3] + (2^(2/3)*(4 + 3*x))/(Sqrt[3]*(28 + 54*x + 27*x^2)^(1/3))]/(3*2^(2/3)*Sqrt[3]) - Log[2 + 3*
x]/(6*2^(2/3)) + Log[-108 - 81*x + 27*2^(1/3)*(28 + 54*x + 27*x^2)^(1/3)]/(6*2^(2/3))

Rule 752

Int[1/(((d_.) + (e_.)*(x_))*((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(1/3)), x_Symbol] :> With[{q = Rt[-3*c*e^2*(2*c
*d - b*e), 3]}, -Simp[(Sqrt[3]*c*e*ArcTan[1/Sqrt[3] - (2*(c*d - b*e - c*e*x))/(Sqrt[3]*q*(a + b*x + c*x^2)^(1/
3))])/q^2, x] + (-Simp[(3*c*e*Log[d + e*x])/(2*q^2), x] + Simp[(3*c*e*Log[c*d - b*e - c*e*x + q*(a + b*x + c*x
^2)^(1/3)])/(2*q^2), x])] /; FreeQ[{a, b, c, d, e}, x] && NeQ[2*c*d - b*e, 0] && EqQ[c^2*d^2 - b*c*d*e + b^2*e
^2 - 3*a*c*e^2, 0] && NegQ[c*e^2*(2*c*d - b*e)]

Rubi steps

\begin {align*} \int \frac {1}{(2+3 x) \sqrt [3]{28+54 x+27 x^2}} \, dx &=-\frac {\tan ^{-1}\left (\frac {1}{\sqrt {3}}+\frac {2^{2/3} (4+3 x)}{\sqrt {3} \sqrt [3]{28+54 x+27 x^2}}\right )}{3\ 2^{2/3} \sqrt {3}}-\frac {\log (2+3 x)}{6\ 2^{2/3}}+\frac {\log \left (-108-81 x+27 \sqrt [3]{2} \sqrt [3]{28+54 x+27 x^2}\right )}{6\ 2^{2/3}}\\ \end {align*}

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Mathematica [C]  time = 0.08, size = 127, normalized size = 1.23 \begin {gather*} -\frac {\sqrt [3]{\frac {9 x-i \sqrt {3}+9}{3 x+2}} \sqrt [3]{\frac {9 x+i \sqrt {3}+9}{3 x+2}} F_1\left (\frac {2}{3};\frac {1}{3},\frac {1}{3};\frac {5}{3};-\frac {3+i \sqrt {3}}{9 x+6},\frac {-3+i \sqrt {3}}{9 x+6}\right )}{2\ 3^{2/3} \sqrt [3]{27 x^2+54 x+28}} \end {gather*}

Warning: Unable to verify antiderivative.

[In]

Integrate[1/((2 + 3*x)*(28 + 54*x + 27*x^2)^(1/3)),x]

[Out]

-1/2*(((9 - I*Sqrt[3] + 9*x)/(2 + 3*x))^(1/3)*((9 + I*Sqrt[3] + 9*x)/(2 + 3*x))^(1/3)*AppellF1[2/3, 1/3, 1/3,
5/3, -((3 + I*Sqrt[3])/(6 + 9*x)), (-3 + I*Sqrt[3])/(6 + 9*x)])/(3^(2/3)*(28 + 54*x + 27*x^2)^(1/3))

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IntegrateAlgebraic [A]  time = 0.22, size = 201, normalized size = 1.95 \begin {gather*} \frac {\log \left (-2 \sqrt [3]{27 x^2+54 x+28}+3\ 2^{2/3} x+4\ 2^{2/3}\right )}{9\ 2^{2/3}}-\frac {\log \left (9 \sqrt [3]{2} x^2+2 \left (27 x^2+54 x+28\right )^{2/3}+\left (3\ 2^{2/3} x+4\ 2^{2/3}\right ) \sqrt [3]{27 x^2+54 x+28}+24 \sqrt [3]{2} x+16 \sqrt [3]{2}\right )}{18\ 2^{2/3}}-\frac {\tan ^{-1}\left (\frac {\frac {\sqrt [3]{27 x^2+54 x+28}}{\sqrt {3}}+2^{2/3} \sqrt {3} x+\frac {4\ 2^{2/3}}{\sqrt {3}}}{\sqrt [3]{27 x^2+54 x+28}}\right )}{3\ 2^{2/3} \sqrt {3}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[1/((2 + 3*x)*(28 + 54*x + 27*x^2)^(1/3)),x]

[Out]

-1/3*ArcTan[((4*2^(2/3))/Sqrt[3] + 2^(2/3)*Sqrt[3]*x + (28 + 54*x + 27*x^2)^(1/3)/Sqrt[3])/(28 + 54*x + 27*x^2
)^(1/3)]/(2^(2/3)*Sqrt[3]) + Log[4*2^(2/3) + 3*2^(2/3)*x - 2*(28 + 54*x + 27*x^2)^(1/3)]/(9*2^(2/3)) - Log[16*
2^(1/3) + 24*2^(1/3)*x + 9*2^(1/3)*x^2 + (4*2^(2/3) + 3*2^(2/3)*x)*(28 + 54*x + 27*x^2)^(1/3) + 2*(28 + 54*x +
27*x^2)^(2/3)]/(18*2^(2/3))

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fricas [B]  time = 2.86, size = 214, normalized size = 2.08 \begin {gather*} -\frac {1}{18} \cdot 4^{\frac {1}{6}} \sqrt {3} \arctan \left (\frac {4^{\frac {1}{6}} {\left (2 \cdot 4^{\frac {2}{3}} \sqrt {3} {\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {2}{3}} {\left (3 \, x + 4\right )} + 4^{\frac {1}{3}} \sqrt {3} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} - 4 \, \sqrt {3} {\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {1}{3}} {\left (9 \, x^{2} + 24 \, x + 16\right )}\right )}}{18 \, {\left (9 \, x^{3} + 54 \, x^{2} + 84 \, x + 40\right )}}\right ) - \frac {1}{72} \cdot 4^{\frac {2}{3}} \log \left (\frac {4^{\frac {2}{3}} {\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {2}{3}} + 4^{\frac {1}{3}} {\left (9 \, x^{2} + 24 \, x + 16\right )} + 2 \, {\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {1}{3}} {\left (3 \, x + 4\right )}}{9 \, x^{2} + 12 \, x + 4}\right ) + \frac {1}{36} \cdot 4^{\frac {2}{3}} \log \left (\frac {4^{\frac {1}{3}} {\left (3 \, x + 4\right )} - 2 \, {\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {1}{3}}}{3 \, x + 2}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(2+3*x)/(27*x^2+54*x+28)^(1/3),x, algorithm="fricas")

[Out]

-1/18*4^(1/6)*sqrt(3)*arctan(1/18*4^(1/6)*(2*4^(2/3)*sqrt(3)*(27*x^2 + 54*x + 28)^(2/3)*(3*x + 4) + 4^(1/3)*sq
rt(3)*(27*x^3 + 54*x^2 + 36*x + 8) - 4*sqrt(3)*(27*x^2 + 54*x + 28)^(1/3)*(9*x^2 + 24*x + 16))/(9*x^3 + 54*x^2
+ 84*x + 40)) - 1/72*4^(2/3)*log((4^(2/3)*(27*x^2 + 54*x + 28)^(2/3) + 4^(1/3)*(9*x^2 + 24*x + 16) + 2*(27*x^
2 + 54*x + 28)^(1/3)*(3*x + 4))/(9*x^2 + 12*x + 4)) + 1/36*4^(2/3)*log((4^(1/3)*(3*x + 4) - 2*(27*x^2 + 54*x +
28)^(1/3))/(3*x + 2))

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{{\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {1}{3}} {\left (3 \, x + 2\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(2+3*x)/(27*x^2+54*x+28)^(1/3),x, algorithm="giac")

[Out]

integrate(1/((27*x^2 + 54*x + 28)^(1/3)*(3*x + 2)), x)

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maple [F]  time = 4.72, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (3 x +2\right ) \left (27 x^{2}+54 x +28\right )^{\frac {1}{3}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(3*x+2)/(27*x^2+54*x+28)^(1/3),x)

[Out]

int(1/(3*x+2)/(27*x^2+54*x+28)^(1/3),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{{\left (27 \, x^{2} + 54 \, x + 28\right )}^{\frac {1}{3}} {\left (3 \, x + 2\right )}}\,{d x} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(2+3*x)/(27*x^2+54*x+28)^(1/3),x, algorithm="maxima")

[Out]

integrate(1/((27*x^2 + 54*x + 28)^(1/3)*(3*x + 2)), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {1}{\left (3\,x+2\right )\,{\left (27\,x^2+54\,x+28\right )}^{1/3}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/((3*x + 2)*(54*x + 27*x^2 + 28)^(1/3)),x)

[Out]

int(1/((3*x + 2)*(54*x + 27*x^2 + 28)^(1/3)), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (3 x + 2\right ) \sqrt [3]{27 x^{2} + 54 x + 28}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(2+3*x)/(27*x**2+54*x+28)**(1/3),x)

[Out]

Integral(1/((3*x + 2)*(27*x**2 + 54*x + 28)**(1/3)), x)

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